Правильный ответ
Правильный ответ: SELECT id, name_i FROM instruments WHERE name_i LIKE "д*";
Варианты ответа
- A.SELECT id, name_i FROM instruments WHERE name="д*";
- B.SELECT id, name_i FROM instruments WHERE name_i LIKE "д";
- C.SELECT * FROM instruments WHERE name_i LIKE "д*";
- D.SELECT id, name_i FROM instruments WHERE name_i LIKE "д*";верно