Дұрыс жауапДұрыс жауап: (−2π3+2πk, 2π3+2πk),k∈Z\left( -\frac{2\pi}{3} + 2\pi k,\; \frac{2\pi}{3} + 2\pi k \right),\quad k \in \mathbb{Z}Жауап нұсқаларыA.(π3+2πk, 2π3+2πk),k∈Z\left( \frac{\pi}{3} + 2\pi k,\; \frac{2\pi}{3} + 2\pi k \right),\quad k \in \mathbb{Z}B.(π3−2πk, 2π3+2πk),k∈Z\left( \frac{\pi}{3} - 2\pi k,\; \frac{2\pi}{3} + 2\pi k \right),\quad k \in \mathbb{Z}C.(−2π6+2πk, 2π3+2πk),k∈Z\left( -\frac{2\pi}{6} + 2\pi k,\; \frac{2\pi}{3} + 2\pi k \right),\quad k \in \mathbb{Z}D.(−2π3+2πk, 2π3+2πk),k∈Z\left( -\frac{2\pi}{3} + 2\pi k,\; \frac{2\pi}{3} + 2\pi k \right),\quad k \in \mathbb{Z}дұрыс