Дұрыс жауапДұрыс жауап: (−1)k+1π3+2πk,k∈Z(-1)^{k+1}\frac{\pi}{3} + 2\pi k,\quad k \in \mathbb{Z}Жауап нұсқаларыA.(−1)k+1π4+2πk,k∈Z(-1)^{k+1}\frac{\pi}{4} + 2\pi k,\quad k \in \mathbb{Z}B.(−1)k+1π6+πk,k∈Z(-1)^{k+1}\frac{\pi}{6} + \pi k,\quad k \in \mathbb{Z}C.(−1)k+1π3+2πk,k∈Z(-1)^{k+1}\frac{\pi}{3} + 2\pi k,\quad k \in \mathbb{Z}дұрысD.(−1)k+12π6+2πk,k∈Z(-1)^{k+1}\frac{2\pi}{6} + 2\pi k,\quad k \in \mathbb{Z}