Дұрыс жауапДұрыс жауап: (π4+πk;π4−πk), k∈Z\left( \frac{\pi}{4} + \pi k; \frac{\pi}{4} - \pi k \right),\ k \in \mathbb{Z}Жауап нұсқаларыA.(π4+πk;π2−πk), k∈Z\left( \frac{\pi}{4} + \pi k; \frac{\pi}{2} - \pi k \right),\ k \in \mathbb{Z}B.(π3+πk;π2−πk), k∈Z\left( \frac{\pi}{3} + \pi k; \frac{\pi}{2} - \pi k \right),\ k \in \mathbb{Z}C.(πk;π6+πk), k∈Z\left( \pi k; \frac{\pi}{6} + \pi k \right),\ k \in \mathbb{Z}D.(π4+πk;π4−πk), k∈Z\left( \frac{\pi}{4} + \pi k; \frac{\pi}{4} - \pi k \right),\ k \in \mathbb{Z}дұрыс